How to tell if a number is divisible by 12

12 is where the pick-two-factors approach bites back. 12 is 2 × 6 and also 3 × 4, but only one of those pairs gives a working test.

The rule

A number is divisible by 12 when it divides by 3 and by 4.

How to check it

  1. Add the digits. If the total is a multiple of 3, the first half passes.
  2. Look at the last two digits. If they make a multiple of 4, the second half passes.
  3. Both have to pass for the number to divide by 12.

Worked examples

Is 4620 divisible by 12?

4 + 6 + 2 + 0 = 12 → multiple of 3 ✓ last two digits 20 = 4 × 5 ✓

Both pass, so yes. 4620 = 12 × 385.

Is 42 816 divisible by 12?

4 + 2 + 8 + 1 + 6 = 21 → multiple of 3 ✓ last two digits 16 = 4 × 4 ✓

Yes. 42 816 = 12 × 3568.

Is 4626 divisible by 12?

4 + 6 + 2 + 6 = 18 → multiple of 3 ✓ last two digits 26 → not a multiple of 4 ✗

No. It divides by 6, but not by 12.

Why 3 and 4, and not 2 and 6

A pair of tests only proves divisibility by their product when the two numbers share no divisor apart from 1. 3 and 4 share nothing but 1, so passing both means the number contains a 3 and two 2s, which is a 12.

2 and 6 overlap: 6 already contains a 2, so passing both only proves the number contains a 6 and at least one 2, which it already had. 18 divides by 2 and by 6 and does not divide by 12.

The same rule of thumb settles other composites: for 15 test 3 and 5, for 20 test 4 and 5, for 24 test 3 and 8.

Where it goes wrong

Questions people ask

What about 24, 36 or 48?

Same method with coprime halves: 24 is 3 and 8, 36 is 4 and 9, 48 is 3 and 16.

Is there a single-step rule for 12?

No, and there does not need to be: two rules a child already knows are faster than any special-purpose procedure.

Related rules